(2a+3b)whole cube -(2a+3b)whole cube
Answers
Answered by
18
(2a + 3b) ³ - ( 2a + 3b) ³ =0
As,
= 8a³ + 27 b³ + 18ab( 2a+3b ) - [ 8a³ + 27b³ + 18ab( 2a+ 3b) ]
= 8a³ + 27 b³ + 36a²b + 52ab² - 8a³ - 27b³ - 36a²b - 52ab²
= 0
hope it helps......
we have used the formula
(x+y)³ = x³ + y³ + 3xy ( x+y)
and here x = 2a and y = 3b
plz mark me as brainliest......
As,
= 8a³ + 27 b³ + 18ab( 2a+3b ) - [ 8a³ + 27b³ + 18ab( 2a+ 3b) ]
= 8a³ + 27 b³ + 36a²b + 52ab² - 8a³ - 27b³ - 36a²b - 52ab²
= 0
hope it helps......
we have used the formula
(x+y)³ = x³ + y³ + 3xy ( x+y)
and here x = 2a and y = 3b
plz mark me as brainliest......
Anonymous:
meghna from punjab
Answered by
8
Hey Friends,
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(2a + 3b)^3 - (2a + 3b)^3
=[8a^3 +27b^3 +18ab(2a+3b) ] - [8a^3 + 27b^3 + 18ab(2a + 3b)]
=8a^3 +27b^3 +18ab(2a+3b) -8a^3 - 27b^3 - 18ab(2a + 3b)
=0 [all terms are cancle and become zero]
HOPE IT'S HELP YOU!!!!
_______________________________
_______________________________
(2a + 3b)^3 - (2a + 3b)^3
=[8a^3 +27b^3 +18ab(2a+3b) ] - [8a^3 + 27b^3 + 18ab(2a + 3b)]
=8a^3 +27b^3 +18ab(2a+3b) -8a^3 - 27b^3 - 18ab(2a + 3b)
=0 [all terms are cancle and become zero]
HOPE IT'S HELP YOU!!!!
_______________________________
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