Question

2A+4B=3C+4D limiting reagent​

Answer 1

Answer:

2A+4B⟶3C+4D

5 6

Limiting reactant is declared which have lowest ratio of

coefficient

Moles

for reactant.

For A:

2

5

=2.5

For B:

4

6

=1.5

⇒B is limiting reagent

2A+4B⟶3C+4D

5 6

Here, 5 mole of A need 10 mole of B to react, thus B is a limiting agent.

3 moles of A can react with 6 moles of B, thus the no. of moles of C formed =

2

3

×3=4.5 mol

Hence, option B is correct.

Explanation:

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