Question

2A + 4B  3C + 4D ; When 8 moles of A react with 9 moles of B ,then
i)Which is the limiting reagent?
ii) Calculate the amount of C formed.

Answer 1

Answer:

Explanation:

2A+4B⟶3C+4D

2A=5 moles

4B=6 moles

The limiting agent is B.

as 5 moles of A requres 10 moles of B but only 6 moles are present.

Hence, 2 moles of A=4 mole of B.

x=6 moles of B.

x=  

4

2×6

​

=3 moles.

Amount of C consumed =  

2

3×3

​

=4.5 moles of C.

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