(2a-4b-5c)sqaure-(2a+4b-5c) square
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According to the equation,
(a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ca
So we get,
Using the formula we can it write it as
(−3a+4b−5c)
2
=(−3a)
2
+(4b)
2
+(−5c)
2
+2(−3a)(4b)+2(4b)(−5c)+2(−5c)(−3a)
On further calculation we get,
(−3a+4b−5c)
2
=9a
2
+16b
2
+25c
2
−24ab−40bc+30ca
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