Math, asked by sanjivlolusare05, 9 months ago

(2a-5)*=(2a+3)(3a-2)

Answers

Answered by chhotiroy343
1

Answer:

(2a-5)=6a^2-4a+9a-6

(2a-5)=6a^2+5a-6

2a-5=6a^2+5a-6

6a^2+3a-1=0

a= -3+-root 33/12

Answered by virendrakumar987319
1

Answer:

Step-by-step explanation:

sorry I am unable to solve it

bt i can say that here in (2a-5)*=(2a+3)(3a-2)

there that no sign means after 2a+3 and 3a-2 between these 2 equations there is no sign means multiplication

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