Math, asked by mdadnankne8349, 1 year ago

2a +5b=103 how many pairs of positive integevvalues can a,b takevsuchbthat a graten than b

Answers

Answered by kevinujunioroy492d
3
so the correct answer is 7
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Answered by abhi178
1
question is -----> 2a +5b=103 how many pairs of positive integers values can a,b take such that a graten than b.

solution :- 2a + 5b = 103
condition : a > b

2a + 5b = 103
Let b = 1, a = 49
b = 3, a = (103 - 5 × 3)/2 = (103 - 15)/2 = 44
b = 5 , a = (103 - 5 × 5)/2 = (103 - 25)/2 = 39
b = 7 , a = (103 - 5 × 7)/2 = (103 - 35)/2 = 34
b = 9 , a = (103 - 5 × 9)/2 = (103 - 45)/2 = 29
b = 11 , a = (103 - 5 × 11)/2 = (103 - 55)/2 = 24
b = 13 , a = (103 - 5 × 13)/2 = (103 - 65)/2 = 19

hence, there are 7 pairs of positive integers values of a and b take such that a is greater than b
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