2a^6-13a^3-24 factorisation by middle breaking method
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Step-by-step explanation:
Given that:-
2a⁶-13a³-24
=>2a⁶-16a³+3a³-24
=>2a³(a³-8)+3(a³-8)
=>(a³-8)(2a³+3)
It can be written as
=>(a³-2³)(2a³+3)
(since a³-b³=(a-b)(a²+ab+b²))
Here, a=a and b=2
=>(a-2)(a²+2a+4)(2a³+3)
2a⁶-13a³-24=(a-2)(a²+2a+4)(2a³+3)
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Answer:
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