2a+6b-3(a+b)² factorize
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2(a+3b) – 3(a+3b) 2
Now by taking (a+3b) as a common factor for the above equation we get,
2(a+3b) – 3(a+3b)2
= (a+3b) (2 – 3(a+3b))
= (a+3b) (2- 3a -9b)
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