Question

2a+8b+10 - [-3a2+7b+16]​

Answer 1

Question:

2a+8b+10-(-3a²+7b+16)

Answer:

$2a+8b+10-(-3a²+7b+16)$

=>$3a²+2a-b-6$

Answer 2

2a+8b+10 - [-3a2+7b+16]​ = (3a² + 2a - b -6)

GIVEN: 2a+8b+10 - [-3a2+7b+16]​
TO FIND: 2a+8b+10 - [-3a2+7b+16]​
SOLUTION:
As we are given in the question,

An expression with a combination of variables and constants.

The number of terms in this expression is 4

The degree of the expression is 2.

As we know,

The degree is the highest power expression.

Now,

Taking up the given expression,

F(x) = 2a+8b+10 - [-3a2+7b+16]​

Using the rule of BODMAS

F(x) = 2a+8b+10+3a²-7b-16

F(x) = 3a² +(8b-7b)+2a+(10-16)

F(x) = 3a² + b + 2a - 6

Therefore,

2a+8b+10 - [-3a2+7b+16]​ = 3a² + b + 2a - 6

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