Question

+2a and - 2a in 0.05s an emf of 8v the self inductnce of coil is

Answer 1

Answer: 0.1 H

Explanation:

E = L * di/dy

:. L = E * dy/di = 8 * 0.05/4 = 0.1

Thus, Coefficient of the self Induction of the coil is: 0.1 H

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