Question

(2a+b)² - (m-n)

Class 8
FACTORISATION (CHAPTER - 14)
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Answer 1

Answer:

-1

Step-by-step explanation:

4 a^2 + 4 a b + b^2 - m + n

(2 a + b)^2 - (m - n)

n = -4 a^2 - 4 a b - b^2 + m

Reduce[(2 a + b)^2 - m + n == 0, {a, b, m, n}, Reals]

n == -4 a^2 - 4 a b - b^2 + m

Reduce[(2 a + b)^2 - m + n == 0, {a, b, m, n}]

{n == -4 a^2 - 4 a b - b^2 + m}

Δ_a = 16 (m - n)

Discriminant[(2 a + b)^2 - m + n, a]

d/dm((2 a + b)^2 - (m - n)) = -1

D[(2 a + b)^2 - m + n, m]

-1

integral((2 a + b)^2 - m + n) dm = m (2 a + b)^2 - m^2/2 + m n + constant

Integrate[(2 a + b)^2 - m + n, m]

(2 a + b)^2 m - m^2/2 + m n