2a + b = 7. b - a = 1
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aanchal93:
find a and B by elimination method
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let L.H.S= 2a+b=1 and R.H.S =7b-a=1
R.H.S= 7b-a=1
=> a=7b-1
on putting the value of a in L.H.S ,we get:
2×(7b-1) + b=1
14b-2+b=1
15b=1+2
b=3/15=1/5
then ,
a = 7×1/5-1
a=7/5 -1
a=(7-5)/5 =2/5
hence a= 2/5 and b=1/5
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