Chemistry, asked by chidiya09, 8 months ago

2A+B =A2B
k=[A] [B]^2 with K=2.0x10^(-6) mol^2 L^2 S^-1 Calculate initial
rate of reaction When [A]=0.1 and [B]=0.2.Calculate rate of reaction after [A] is reduced to 0.06 Mole per litre

Answers

Answered by maazaffan07
1

initial rate of the reaction k=(a)(b)2

(2.0(10^-6) (0.1)(0.2)

8.0(10)-9

when a is reduced to 0.06

the conc of a reactant a (0.1-0.06)

0.04

conc of reactant b is 0.2-0.02

0.18

rate =k (a)(b)

2(10)^-6(0.06)(0.18)

3.89mol

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