2a - b + c = 0 , prove that 4a^2 - b^2 + c^2 + 4ac = 0
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Answer:Given that,
2a-b+c=0
2a+c=b
squaring on both sides we get,
(2a+c)²=(b)²
4a²+c²+4ac=b²
4a²+c²+4ac-b²=0
4a²-b²+c²+4ac=0
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