(2a+b+c)2-(2a+b-c)2 is equal to
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Step-by-step explanation:
Factorising it will give:-
(2a + b + c)² - (2a + b - c )²
= 2c(4a + 2b)
= 4c(2a+b)
Expanding it will give:-
( 2a + b + c)² - (2a + b - c)²
= { 4a² + b² + c² + 4(ab + bc + ca) } - { ( 4a² + b² + c² + 4(ab - bc - ca) }
= 4a²+b²+c²+4ab + 4bc + 4ac - 4a² - b² -c² - 4ab + 4bc + 4ac
= 4bc + 8ac
= 4(bc + 2ac)
Hope it helps
★Additional Information:-
- (a+b)² = a²+b²+2ab
- (a-b)² = a²+b² - 2ab
- a²+b² = (a+b)² - 2ab
- a²-b² = (a+b)(a-b)
- (a+b)² = (a+b)(a+b)
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