(2a-b-c) 2-(a-b-c)2
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wrong ans sorry.......
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(2a-b-c)^-(a-b-c)^
={(2a)^+b^+c^-2×2a×b+2×b×c-2×c×2a}-
(^a+b^+c^-2ab+2bc-2ca)By applying the formula(a-b-c)^
=4a^+b^+c^-4ab+2bc-4ca-a^-b^-c^+2ab-2bc+2ca
=4a^-4ab-4ca-a^+2ab+2ca
=3a^-2ab-2ca
=a(3a-2b-2c ). (Ans)
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