Math, asked by riya9378, 11 months ago

(2a-b-c) 2-(a-b-c)2​

Answers

Answered by neelgreevG
0

wrong ans sorry.......

Answered by lipimohapatra01
1

(2a-b-c)^-(a-b-c)^

={(2a)^+b^+c^-2×2a×b+2×b×c-2×c×2a}-

(^a+b^+c^-2ab+2bc-2ca)By applying the formula(a-b-c)^

=4a^+b^+c^-4ab+2bc-4ca-a^-b^-c^+2ab-2bc+2ca

=4a^-4ab-4ca-a^+2ab+2ca

=3a^-2ab-2ca

=a(3a-2b-2c ). (Ans)

Similar questions
Math, 11 months ago