(2a + b)(c − 2d) + (a − b)(2c + 3d) + 4(ac + bd)
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(2a+b)(c−2d)+(a−b)(2c+3d)+4(ac+bd)
=2ac−4ad+bc−2bd+2ac+3ad−2bc−3bd+4ac+4bd
=8ac−ad−bc−bd
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