Question

2a + b ka whole square - 6a - 3b - 4
$(2a + b) {}^{2} - 6a - 3b - 4$

Answer 1

(2a+b)^2-6a-3a-4
=4a^2+b^2+4ab-6a-3b-4

Hope it helped you

Answer 2

$<b>Heya mate. (^_-). Solution below.$
====================================

We factorise this by the method of taking out a common factor.

• (2a + b)² - 6a - 3b - 4

= (2a + b)² - [3 (2a + b) - 4]

= (2a + b) [(2a + b) - 3 - 4]

= (2a + b) [(2a + b) - 7]

= (2a + b)(2a + b -7)

$<marquee>Hence, your answer is (2a + b)(2a + b - 7).</marquee>$
====================================

Thank you.. ;-)