Question

2a + b = product is an elementary reaction .If the pressure is increased three times of initial pressure the velocity of forward reaction will be

Answer 1

Answer:

Rate of reaction=$\frac{-d[A]}{dt}$

                          =$=-\frac{1}{V} *\frac{dn_{A} }{dt} \\=-\frac{1}{RT} *\frac{dP_{A} }{dt}$

[A]=$\frac{n_{A} }{V}$

P=[A]RT

The reaction is 2A+B⇒product

rate=$K[A]^{2} [B]$

$r_{1} =k[\frac{P}{RT} ]^{2} [\frac{P}{RT} ]------(1)$

pressure is increased by 3times

$r_{2} =K[\frac{3P}{RT} ]^{2} [\frac{3P}{RT} ]----------(2)$

so based on above equations we get

$\frac{r_{2} }{r_{1} } =27$

27 times more

Answer 2

Answer:

Hope it will help you....