2A current flows through an electrical device of resistance 120ohm. (a) calculate the power of the device. (b) what changes to be done in this Device to increase the power of the device without changing potential difference or
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Answer:
480 watt
Explanation:
Explanation:power- I²R
Here I is given as 2A
And resistance is 120 ohm
So applying the formula
2²×120
480watt
P=VI
V=IR
Therefore,. P=I²R
You Can Either Increase The Current Flowing Through The Circuit Or Increase The Resistance Of The Circuit.
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