(2a-x/2)^5 expand the following
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Answer:
(x
2
+2a)
5
⇒
5
C
0
(x
2
)
5
+
5
C
1
(x
2
)
4
(2a)+
5
C
3
(x
2
)
3
(2a)
2
+
5
C
2
(x
2
)
2
(2a)
3
+
5
C
4
(x
2
)(2a)
4
+
5
C
5
(2a)
5
⇒ x
10
+5×2ax
8
+10×4a
2
x
6
+10×8a
3
x
4
+5×16a
4
x
2
+32a
5
. [Since
n
C
r
=
r!(n−r)!
n!
]
⇒ x
10
+10ax
8
+40a
2
x
6
+80a
3
x
4
+80a
4
x
2
+32a
5
.
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