Math, asked by SatishKedu, 2 months ago

( –2a2 − 13ab − 4c) and ( – 2a2 + 3ab + 2b + 5c)

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Answered by bhabhrpankaj50
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Answered by yaeeshkhan0410
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Step-by-step explanation:

Expressions and Identities ...

(i) 5xyz2 – 3zy. In the expression 5xyz2 – 3zy, the terms are 5xyz2 and –3zy. ... (i) (a2) × (2a2 2) × (4a26). (iv) x × x2 × x3 ... –4ac + 4bc + 4c2 – 3a2 – 3ab – 3ac + 2ab – 2b2 + 2bc. = –3a2

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