Question

2a2+2√6ab+3b2 solve this question

Answer 1

hope this helps you...✌^_^

Answer 2

Answer:

Answer of this question is = $(\sqrt{2} a+\sqrt{3} b)^{2}$ .

Step-by-step explanation:

Given that,

= $2a^{2} +2\sqrt{6} ab + 3b^{2}$

To solve the question

Require some basic knowledge of Binary Equations

Explanation

Now we can separate  $2\sqrt{6} ab$ this into two parts,

So we get,

$2a^{2} +\sqrt{6} ab +\sqrt{6} ab + 3b^{2}$

Now we can write  $\sqrt{6}$  into $\sqrt{2}$×$\sqrt{3}$

And $2= \sqrt{2}$ ×$\sqrt{2}$ , $3=$  $\sqrt{3}$    × $\sqrt{3}$

So we get,

=$(\sqrt{2}$ ×$\sqrt{2}$$a^{2}+$$\sqrt{2} \sqrt{3} ab) + (\sqrt{2} \sqrt{3} ab+\sqrt{3}\sqrt{3} b^{2})$

Now we can take $\sqrt{2}a$, and $\sqrt{3}b$ as common.

So we get,

= $\sqrt{2}a (\sqrt{2} a +\sqrt{3}b) + \sqrt{3}b(\sqrt{2}a+ \sqrt{3}b)$

Now we can take $(\sqrt{2}a+\sqrt{3}b)$, as common.

So we get,

= $(\sqrt{2}a+\sqrt{3}b)(\sqrt{2}a+\sqrt{3}b)$

So we can write,

= $(\sqrt{2}a+\sqrt{3}b)^{2}$

Answer of that Question is $(\sqrt{2}a+\sqrt{3}b)^{2}$.

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