Math, asked by Adithyasksksks8993, 3 months ago

(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)

Answers

Answered by kevhan
8

Answer:

(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)(2a²+3b)

= (2a²+3b) ^ 8

= 64 (9 b^2 (a^4 + 3 a^2 b) + 2 (a^4 + 3 a^2 b)^2)^2 + 1296 b^4 (9 b^2 (a^4 + 3 a^2 b) + 2 (a^4 + 3 a^2 b)^2) + 6561 b^8

= 256 a^16 + 3072 a^14 b + 16128 a^12 b^2 + 48384 a^10 b^3 + 90720 a^8 b^4 + 108864 a^6 b^5 + 81648 a^4 b^6 + 34992 a^2 b^7 + 6561 b^8

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