Math, asked by rupkathanag3, 8 months ago

2a²+b²-1 where a =0 and b = 1​

Answers

Answered by chinky1993sharma
3

Answer:

0 step by step explanation is given in image provided

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Answered by Mysteryboy01
0

  = {2a}^{2}  +  {b}^{2}  - 1

 = 2( {0})^{2}  + ( {1})^{2}  - 1

 = 0 + 1 - 1

 = 0

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