Question

2a² - b²c + 3abc (a = 1 , b = 2 , c = - 1)
find the value of the following ​

Answer 1

Answer:

Given,

a=12,d=6,a

n

=252

a

n

=a+(n−1)d

252=12+(n−1)6

40=n−1

∴n=41

S

n

=

2

n(a+a

n

)

=

2

41(12+252)

=5412

Answer 2

hope it helps u mate ☺️☺️