Math, asked by nehakhandekar2002, 8 months ago

2a³+11a²+19a+15 by 2a+5

Answers

Answered by satyendraprsad

4

Answer:

2a(2a³+11a²+19a+15) ± 5(2a²+11a²+19+15),

4a⁴+22a³+38a²+30a³+10a³+55a²+95a+75

4a⁴+32a³+93a²+125a+75 Answer

Answered by nalanagulajagadeesh

7

Answer:

go through following attachment

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