Question

(2ab^2 + 3abc)(2xy + 3ab - 4ca)

Answer 1

$\underbrace \text{Answer:-}$

$\rm{(2a {b}^{2} + 3abc)(2xy + 3ab - 4ca)}$

$= \tt{2a {b}^{2} (2xy + 3ab - 4ca) + 3abc(2xy + 3ab - 4ca)}$

$= \tt{ \red{4a {b}^{2} xy + 6 {a}^{2} {b}^{3} + { a}^{2} {b}^{2} c + 6abcxy }}$