2ab^2c - 2a + 3b^3c - 3b - 4b^2c^2 + 4c
factorise
Answers
Answered by
0
Answer:
- 2 a b is correct answer j
Answered by
0
Answer:
2ab^2c - 2a + 3b^3c - 3b - 4b^2c^2 + 4c
factorise
Similar questions