Question

(2ab-2cd)^2-(a^2+b^2-c^2-d^2)^2

Answer 1

Answer:

=(a+b−c−d)(a+b+c+d)

Step-by-step explanation:

a ^ 2 +b^  2  −c^  2  −d^  2 +2ab−2cd

=(a  ^2  +b ^ 2 +2ab)−(c ^ 2  +d^  2  +2cd)

=(a+b) ^ 2  −(c+d)^  2 [∴a^  2  −b^  2  =(a+b)(a−b)]

=((a+b)−(c+d))((a+b)+(c+d))

=(a+b−c−d)(a+b+c+d)

Answer 2

Answer:

=(a+b−c−d)(a+b+c+d)

Step-by-step:

a2 +b 2 −c 2 −d 2+2ab−2cd

=(a 2+b 2 +2ab)−(c 2+d 2 +2cd)

=(a+b) 2 −(c+d) 2 [∴a 2 −b 2

=(a+b)(a−b)]

=((a+b)−(c+d))((a+b)+(c+d))

=(a+b−c−d)(a+b+c+d)