Question

(2ab-3b-2c) (4a²+9b²+4c²+6ab-6bc+4ca)
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Answer 1

Answer:

Given,

(2a−3b−2c)(4a

2

+9b

2

+4c

2

+6ab–6bc+4ca)

=(2a−3b−2c)[(2a)

2

+(3b)

2

+(2c)2–2a×(−3b)–(−3b)×(−2c)–(−2c)×2a]

=(2a)

3

+(3b)

3

+(−2c)3−3×2a×(−3b)(−2c)

=8a

3

–21b

3

−8c

3

–36abc

Step-by-step explanation:

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Answer 2

Answer:

cube of(2ab-3b-2c)

ok

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