Math, asked by sumanshukla8076, 4 months ago

2ab+3bc+6ca,3ab-5bc-16ca and -5ab+2bc+10ca
(find the sum)​

Answers

Answered by rajvermaup1990
1

Answer:

Solution :

When a= 2, b = 5, c = 8

3ab + 10bc - 2ac

= (3 x 2 x 5) + (10 x 5 x 8) - (2 x 2 x 5 x 8)

= 30 + 400 - 160

= 430 - 160

= 270

∴ 3ab + 10bc - 2ac = 270

Step-by-step explanation:

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