2ab+3bc+6ca,3ab-5bc-16ca and -5ab+2bc+10ca
(find the sum)
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Answer:
Solution :
When a= 2, b = 5, c = 8
3ab + 10bc - 2ac
= (3 x 2 x 5) + (10 x 5 x 8) - (2 x 2 x 5 x 8)
= 30 + 400 - 160
= 430 - 160
= 270
∴ 3ab + 10bc - 2ac = 270
Step-by-step explanation:
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