(2ab+3bc-ca) + (4bc+2ca-3ab) - (ab-bc-ca)
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Answered by
8
2ab + 3bc-ca+4bc+2ca-3ab-ab+bc+ca
=2ab-4ab+3bc+5bc-ca+3ca
=-2ab+8bc+2ca
=8bc-2ab+2ca
@Marcia Royal
=2ab-4ab+3bc+5bc-ca+3ca
=-2ab+8bc+2ca
=8bc-2ab+2ca
@Marcia Royal
harsha180901:
"8bc-2ab+2ca" is the right answer.
Calculation mistake
Corrected
See
Answered by
3
(2ab+3bc-ca)+(4bc+2ca-3ab)-(ab-bc-ca)= 2ab+3bc-ca+4bc+2ca-3ab -ab+bc+ca
=(2ab-3ab-ab)+(3bc+4bc+bc) +(-ca+2ca+ca)
=-2ab+8bc+2ca.
Hope This Helps.
=(2ab-3ab-ab)+(3bc+4bc+bc) +(-ca+2ca+ca)
=-2ab+8bc+2ca.
Hope This Helps.
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