Math, asked by hussainakbar5675, 1 month ago

2ab+3ca+6abc, -5ab+2bc-5abc, 3ab-2bc-3ca

Answers

Answered by Anwasha

4

Answer:

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Step-by-step explanation:

=2ab+3ca+6abc+(‐5ab+2bc‐5abc)+(3ab‐2bc‐3ca)

=2ab+3ca+6abc‐5ab+2bc‐5abc+3ab‐2bc‐3ca

=‐3ab+3ab+3ca‐3ca+6abc-5abc+2bc‐2bc

=0+0+abc+0

=abc

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