Question

(2ab+a^2+b^2-c^2)÷(2ab+a^2+b^2-c^2)​

Answer 1

Answer:

(2ab+a^2+b^2-c^2)÷(2ab+a^2+b^2-c^2)

(2ab+a^2+b^2-c^2)

_______________

(2ab+a^2+b^2-c^2)

$= {a}^{2} + {b}^{2} + {c}^{2}$

Answer 2

ANSWER➡1

Step-by-step explanation:

$\bf\huge \: \frac{ \cancel{2ab + {a}^{2} + {b}^{2} - {c}^{2}} }{ \cancel{2ab + {a}^{2} + {b}^{2} - {c}^{2}} }$

$\sf\ \implies: 1$

$\huge \bigstar\frac{a}{a} = 1$