2ab²+a²-2a²b-b² (factorise)
Answers
Answered by
2
Step-by-step explanation:
Given :-
2ab²+a²-2a²b-b²
To find :-
Factorise the expression ?
Solution :-
Given expression is 2ab²+a²-2a²b-b²
It can be written as
=> (2ab²-2a²b)+(a²-b²)
=> 2ab(b-a) -(b²-a²)
=> 2ab(b-a)-(b+a)(b-a)
=> (b-a)[2ab-(b+a)]
=> (b-a)(2ab-b-a)
Answer :-
The factorization of the expression is
(b-a)(2ab-b-a)
Check:-
(b-a)(2ab-b-a)
=> b(2ab-b-a)-a(2ab-b-a)
=> 2ab²-b²-ab-2a²b+ab+a²
=> 2ab²-b²-2a²b+a²
=> 2ab²+a²-2a²b-b²
Verified the given relations in the given problem.
Similar questions