Math, asked by krishnakumar27022005, 9 months ago

2ab²c-2a+3b³c-3b-4b²c²+4c​

Answers

Answered by anuyadav91
2

Step-by-step explanation:

2ab²c-2a+3b³c-3b-4b²c²+4c

2ab²c-4b²c²-2a+3b³c-3b+4c

2b²c(a-2c)-2a+3b(b²c-1)+4c

Answered by asmaparvin2755
4

2ab2c – 2a + 3b3c – 3b – 4b2c2 + 4c

= 2a (b2c – 1) + 3b (b2c – 1) – 4c (b2c – 1)

= (b2c – 1) (2a + 3b – 4c)

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