Question

2abc, + 8ab2 + 3a²c + 8bc, when a = 1, b = 1, and c = 2.​

Answer 1

Answer:

=> 2(1)(1)(2) + 8(1)(1)2 + 2(1)²(2) + 8(1)(2)

=> 4+16+4+16

=> 40

hope it helps u

Answer 2

Step-by-step explanation:

$2abc + 8a {b}^{2} + 3a²c + 8bc \\ 2×1×1×2+8 \times 1 \times {1}^{2} + 3 \times {1}^{2} \times 2 + 8 \times 1 \times 2$

$4 + 8 + 6 + 16 \\ 10 + 22 \\ 32$

32 is answer