Math, asked by charviii6153, 7 months ago

(2ac+4ab +7bc )+(13ac-3ab+7bc )=26ac^2 -12ab^2+49bc^2

Answers

Answered by swastipandeyin

0

Step-by-step explanation:

(2ac+4ab +7bc )+(13ac-3ab+7bc )=26ac^2 -12ab^2+49bc^2

=2ac+4ab +7bc +13ac-3ab+7bc =26ac^2 -12ab^2+49bc^2

=15ac+ab+14bc=26ac^2 -12ab^2+49bc^2

=26ac^2 -12ab^2+49bc^2-15ac-ab-14bc=0

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