2acube +16b cube -5a-10b
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2a3+16b3
Final result :
2 • (a + 2b) • (a2 - 2ab + 4b2)
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(2 • (a3)) + 24b3
Step 2 :
Equation at the end of step 2 :
2a3 + 24b3
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
2a3 + 16b3 = 2 • (a3 + 8b3)
Trying to factor as a Sum of Cubes :
4.2 Factoring: a3 + 8b3
Theory : A sum of two perfect cubes, a3 + b3can be factored into :
(a+b) • (a2-ab+b2)
Proof : (a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+b3
Check : 8 is the cube of 2
Check : a3 is the cube of a1
Check : b3 is the cube of b1
Factorization is :
(a + 2b) • (a2 - 2ab + 4b2)
Final result :
2 • (a + 2b) • (a2 - 2ab + 4b2)
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(2 • (a3)) + 24b3
Step 2 :
Equation at the end of step 2 :
2a3 + 24b3
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
2a3 + 16b3 = 2 • (a3 + 8b3)
Trying to factor as a Sum of Cubes :
4.2 Factoring: a3 + 8b3
Theory : A sum of two perfect cubes, a3 + b3can be factored into :
(a+b) • (a2-ab+b2)
Proof : (a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+b3
Check : 8 is the cube of 2
Check : a3 is the cube of a1
Check : b3 is the cube of b1
Factorization is :
(a + 2b) • (a2 - 2ab + 4b2)
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