Question

2as=v^2-u^2

please send me answer​

Answer 1

Answer:

we know that

$a=(v-u)/t\\ at=v-u\\ at+u=v$               .. (let eq I)

we know that,

$Avg. velocity = (u+v)/2$

$=s/t =(u+u+at)/2$                          (v=u+at from eq I)

$= s=(2u+at)/2$

     $=(2ut+at^{2} )/2\\=2ut/2 + at^{2}/2\\=ut+(at^{2})/2$          ..(let eq II)

As we know

$Avg. velocity = (u+v)/2$

$s/t =(u+v)/2\\s=t(u+v)/2$        ..(let eq III)

From eq I

$v=u+at\\v-u=at\\(v-u)/a=t$

Putting value of (v-u)/a in equation III

$s=[(v+u)/2 ] * [(v-a)/2]\\s=(v^{2} -u^{2})/2a\\2as=v^{2}-u^{2}\\v^{2}=2as+u^{2}$

           

Hence derived!!!

HOPE THIS HELPS TO YOU!