Question

2ay²-5aby =0 a≠0 find the root of quadratic equations by using method of factorization.​

Answer 1

Answer:

y=-a or  y=5b/2

Step-by-step explanation:

2ay²-5aby=0

ay(2y-5b)=0

ay=0 or 2y-5b=0

y=-a  or  2y=5b

                y=5b/2

hope it helps♥♥♥♥♥♥

Answer 2

Answer:

=>2ay^2 - 5aby =0

=> ay (2y - 5b ) =0

=> hence, ay= 0  => y= 0

=>2y- 5b= 0

=>2y= 5b  => y= 5b/2

Hence, roots are :

y=0 & y= 5b/2