Question

2b^2+8ab+4ac+bc factorise

Answer 1

(2b2+bc)+(8ab+4ac)
b(2b+c)+4a(2b+c)
(b+4a)(2b+c)

Answer 2

Answer :

Now,

2b² + 8ab + 4ac + bc

= 2b (b + 4a) + c (4a + b)

= (4a + b) (2b + c),

which is the required factorization.

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