Question

2b-a-5c-32b+3a-(b-c-a)​

Answer 1

Answer:

3a-31b-4c

Step-by-step explanation:

2b-a-5c-32b+3a-(b-c-a)

=2b-a-5c-32b+3a-b+c+a

=-a+a+3a+2b-32b-b-5c+c

=3a-31b-4c

I think it might help you!

Answer 2

Answer:

$\huge\boxed{-31b+3a-4c}$

Step-by-step explanation:

To solve this problem, first you have to isolate by the a, b, or c from one side of the equation.

Given:

2b-a-5c-32b+3a-(b-c-a)​

Solutions:

First, you have to solve parenthesis.

$\displaystyle -(b-c-a)$

$\displaystyle -(b)-(-c)-(-a)$

Change negative sign to positive sign.

$\displaystyle -(-x)=x \quad -(x)=-x$

$\displaystyle -b+c+a$

Rewrite the problem down.

$\displaystyle 2b-a-5c-32b+3a-b+c+a$

Solve.

$\displaystyle 2b-a-5c-32b+3a-b+c+a$

Combine like terms. (Group like terms & switch sides.)

$\displaystyle 2b-32b-b-a+3a+a-5c+c$

Add numbers from left to right.

Add or subtract elements to from left to right numbers.

$\displaystyle 2b-32b-b=-31b$

$\displaystyle -31b-a+3a+a-5c+c$

$\displaystyle -a+3a+a=3a$

$\displaystyle -31b+3a-5c+c$

$\displaystyle -5c+c=-4c$

$\displaystyle \boxed{-31b+3a-4c}$

$\Large\boxed{-31b+3a-4c}$

Therefore, the final answer is -31b+3a-4c.