Question

2b
Find the area of the pentagon ABCDE, where AB=6 cm, BC=8 cm, =​ QC, PQ =6, PE=3​ cm, and QD =4​ cm.

Answer 1

Step-by-step explanation:

x, y, z are integer that are side of an obtuse-angled triangle. If xy = 4, find z.

A. 2

B. 3

C. 1

D. More than one possible value of z exists

Answer 2

Answer:

First find the area of the triangle ABC:

8*6*0.5 = 24

But before that find the length of AC using the pythagoras theory:

$a^{2} +b^{2} = c^{2}$

$6^{2} +8^{2} = c^{2} \\36+64= 100\\\sqrt{100} = 10$

Then with that you can find AP and QC:

10cm-6cm ( PQ) = 4cm

4cm* 0.5 = 2cm.

AP= 2cm and QC= 2cm

Now with that you find he area of the two triangles APE and DQC.

APE = 3 and DQC= 4

But EPQD is an trapezium, so find the area f that which is:

21

Add all together and you will get 52