2b²+32b+128 spilit that
Answers
Answer:
2b²+16b+16b+128
2b(b+8)+16(b+8)
(b+8)(2b+16)
b=-8 ,16/2=8
b= -8 , 8
Answers:Simplifying
2b2 + 32b + 128 = 0
Reorder the terms:
128 + 32b + 2b2 = 0
Solving
128 + 32b + 2b2 = 0
Solving for variable 'b'.
Factor out the Greatest Common Factor (GCF), '2'.
2(64 + 16b + b2) = 0
Factor a trinomial.
2((8 + b)(8 + b)) = 0
Ignore the factor 2.
Subproblem 1
Set the factor '(8 + b)' equal to zero and attempt to solve:
Simplifying
8 + b = 0
Solving
8 + b = 0
Move all terms containing b to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + b = 0 + -8
Combine like terms: 8 + -8 = 0
0 + b = 0 + -8
b = 0 + -8
Combine like terms: 0 + -8 = -8
b = -8
Simplifying
b = -8
Subproblem 2
Set the factor '(8 + b)' equal to zero and attempt to solve:
Simplifying
8 + b = 0
Solving
8 + b = 0
Move all terms containing b to the left, all other terms to the right.
Add '-8' to each side of the equation.
8 + -8 + b = 0 + -8
Combine like terms: 8 + -8 = 0
0 + b = 0 + -8
b = 0 + -8
Combine like terms: 0 + -8 = -8
b = -8
Simplifying
b = -8
Solution
b = {-8, -8}