Physics, asked by shekharkannojiya5, 1 year ago

2bodies a,b having masses in their ratios 3:1 possess same kinetic energy the ratio of the momentum is.

Answers

Answered by Anonymous
58
Hola User____________

Here is Your Answer...!!!!
____________________

⭐Actually welcome to the concept of the KINEMATICS OF A BODY...

⭐Here we have to use...

⭐KINETIC ENERGY = P^2 / 2m

⭐where ... p= momentum of the body ....
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Answered by SmãrtyMohït
51
Here is your solution

\huge\boxed{\red{\bold{Given:-}}}

2 bodies a,b
Their masses in their ratios 3:1

A/q

a:b = m1:m2=3:1

I. e

 \frac{a}{b} = \frac{m1}{m2} = \frac{3}{1} \ \\\\<br /><br />Given\: that \:same \:kinetic\: energy.<br /><br />\\ \\ k.e1 = \frac{p1 {}^{2} }{2m1} \\ \\ k.e2 = \frac{p2 {}^{2} }{2m2} \\ \\ both \: are \: equal<br />\\\\ ke1 = ke2 \\ \frac{p1 {}^{2} }{2m1} = \frac{p2 {}^{2} }{2m2} \\\\ \frac{p1 {}^{2} }{p2 {}^{2} } = \frac{2m1}{2m2} \\\\ \frac{p1 {}^{2} }{p2 {}^{2} } = \frac{2 \times 3}{2 \times 1} \\\\ \frac{p1 {}^{2} }{p2 {}^{2} } = \frac{\cancel6\:{}^{3}}{\cancel2} \\ \\\frac{p1 {}^{} }{p2 {}^{} } = \frac{ \sqrt{3} }{1}

Ratio \: of \:the\: momentum \: is.\\ \sqrt{3} :\: 1

k=p^2/2×mass
p - momentum
m1-mass of a
m2-mass of b

Hope it helps you

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