Question

2by 3-root 5 rationalization​

Answer 1

Answer:

Step-by-step explanation:

oot 3-root 5

(we have to multiply both numerator and denominator by root 3+root 5)

then,

(2×root 3)+(2×root 5)

= ________________

3-5

(taking 2 common)

= 2(root 3 +root 5)

____________

-2

= (root 3 +root 5)÷ (-1)

= -root 3 -root 5

Hope it will help

Answer 2

Answer:

(6+√5)/4

Step-by-step explanation:

$\frac{2}{3 - \sqrt{5} } = \frac{2(3 + \sqrt{5}) }{(3 - \sqrt{5} )(3 + \sqrt{5}) } = \frac{6 + 2 \sqrt{5} }{ {(3)}^{2} - {( \sqrt{5} )}^{2} } = \frac{6 + 2 \sqrt{5} }{9 - 5} = \frac{6 + \sqrt{5} }{4}$

Hope It Helps :)