Question

2by 7 of 482 km find the value​

Answer 1

Answer:

Let speed of first train =xkm/hr

Then speed of other train =(x+4)km/hr

Distance traveled by first train after 3hrs=3xkm

Distance traveled by other train after 3hrs=3(x+4)km=(3x+12)km

Now, distance between them is 20km

So, 3x+(3x+12)+20=482

⇒ 6x+32=482

⇒ 6x=482−32

⇒ 6x=450

∴ x=

6

450

=75km/hr

∴ x+4=75+4=79km/hr

∴ Speed of the trains are 75km/hr and 79km/hr

Step-by-step explanation:

Is this question correct???

Answer 2

Answer:

hii

Step-by-step explanation:

Let speed of first train =xkm/hr

Then speed of other train =(x+4)km/hr

Distance traveled by first train after 3hrs=3xkm

Distance traveled by other train after 3hrs=3(x+4)km=(3x+12)km

Now, distance between them is 20km

So, 3x+(3x+12)+20=482

⇒ 6x+32=482

⇒ 6x=482−32

⇒ 6x=450

∴ x=

6

450

=75km/hr

∴ x+4=75+4=79km/hr

∴ Speed of the trains are 75km/hr and 79km/hr