Question

2c+02=2co ∆g°=-530kj/mol
2mgo=2mg+02 ∆g°=730kj/mol check Spontinity when reduction of mgo with c

Answer 1

Answer:

CHECK THE GIBBS FREE ENERGY

Explanation:

BY ADDING THE GIBBS FREE ENERGY OF BOTH REACTIONS WE GET THE POSITIVE VALUE AS (ΔG=ΔG₁+ΔG₂)=200KJ/MOL

SINCE VALUE IS POSITIVE THUS REACTION WILL NOT BE FEASIBLE .......

FOR SPONTANEITY

ΔG=ΔG°+TΔS

SOLVE FOR IT